Question

What is the conductivity of 0.01 M NaCl solution if resistance and cell constant of NaCl solution are 375 ohms and 0.5 cm^-1 respectively at 298 K?

विकल्प

• 1.333 × 10^-4 Ω^-1 cm^-1

• 7.50 × 10^-3 Ω^-1 cm^-1

• 1.875 × 10^-3 Ω^-1 cm^-1

• 1.333 × 10^-3 Ω^-1 cm^-1

Answer 1

1.333 × 10^-3 Ω^-1 cm^-1 

Explanation:

Conductivity, k = `"Cell constant"/"R" = (0.5  "cm"^-1)/(375  Omega)`

∴ k = 1.333 × 10^-3 Ω^-1 cm^-1