Question

What is the oxidation number of Mn in \[\ce{MnO^{2-}_4}\] ion?

विकल्प

• + 6

• + 8

• - 8

• - 6

Answer 1

+ 6

Explanation:

Oxidation number of Mn in \[\ce{MnO^{2-}_4}\] ion is + 6 \[\ce{MnO^{2-}_4}\]

Let, oxidation of Mn = x

We know that,

oxidation state of O = - 2

Putting the value in formula

x + 4(- 2) = - 2

x - 8 = - 2

x = - 2 + 8

x = + 6