Question

what is the value of `cos^-1 (cos  (13pi)/6)`

विकल्प

• `pi/2`

• `pi/4`

• `pi/6`

• `pi/8`

Answer 1

`pi/6`

Explanation:

`cos^-1 (cos  (13pi)/6)`

`cos^-1 [cos(2pi + pi/6)]`

`cos^-1 [cos(pi/6)] = pi/6`