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प्रश्न
What is the value of frequency at which an e.m wave must be propagated for the D-region of atmosphere to have a refractive index of 0.49? Electron density for D-region is 109 m-3:
विकल्प
3.27 × 105 Hz
3.22 × 105 Hz
3.24 × 105 Hz
3.26 × 105 Hz
MCQ
उत्तर
3.27 × 105 Hz
Explanation:
`mu = sqrt(1 - (81.45 " N")/"V"^2)`
`0.49 = sqrt(1 - (81.45 xx 10^9)/"V"^2)`
`0.24 = 1 - (81.45 xx 10^9)/"V"^2`
V = `(81.45 xx 10^9)^(1//2)/1.24`
= 3.27 × 105 Hz
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