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प्रश्न
What must be subtracted from a3 − 4a2 + 5a − 6 to obtain a2 − 2a + 1?
उत्तर
Let the expression to be subtracted be X.
(a3 − 4a2 + 5a − 6)-X = (a2 − 2a + 1)
X = (a3 − 4a2 + 5a − 6)- (a2 − 2a + 1)
Since '-' sign precedes the parenthesis, we remove it and change the sign of each term within the parenthesis.
X = a3 − 4a2 + 5a − 6- a2 + 2a - 1
Rearranging and collecting the like terms:
X = a3 +(− 4-1)a2 + (5+2)a − 6 - 1
X = a3 −5a2 + 7a − 7
So, a3 −5a2 + 7a − 7 must be subtracted from a3 − 4a2 + 5a − 6 to obtain a2 − 2a + 1.
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