हिंदी

What Sign (+Ve Or −Ve) Has Been Given to the Following on the Basis of Cartesian Sigh Convention? Height of a Real Image. - Science

Advertisements
Advertisements

प्रश्न

What sign (+ve or −ve) has been given to the following on the basis of Cartesian Sigh Convention?  

Height of a real image. 

उत्तर

A negative sign has been given to the height of a real image.
(Because a real image is formed below the principal axis, it's given a negative sign).

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Reflection of Light - Exercise 4 [पृष्ठ १९२]

APPEARS IN

लखमीर सिंग Physics (Science) [English] Class 10
अध्याय 4 Reflection of Light
Exercise 4 | Q 6.1 | पृष्ठ १९२

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

What sign (+ve or −ve) has been given to the following on the basis of Cartesian Sigh Convention? 

Height of a virtual image.


What is the nature of image formed by a concave mirror if the magnification produced by the mirror  

 −2?


Fill in the following blank with suitable word: 

If the magnification has a minus sign, than the image is ......... and .......


An object is placed at a distance of 100 cm from a converging lens of focal length 40 cm.
(i) What is the nature of image?
(ii) What is the position of image?


A convex lens produces a magnification of + 5. The object is placed:
(a) at focus
(b) between f and 2f
(c) at less than f
(d) beyond 2


In order to obtain a magnification of, –0.75 with a convex lens of focal length 8 cm, the object should be placed:
(a) at less than 8 cm
(b) between 8 cm and 16 cm
(c) beyond 16 cm
(d) at 16 cma


What is meant by magnification? Write its expression. What is its sign for real image and virtual image?


A negative sign in the value of magnification indicates that the image is ______.


Assertion: The focal length of the mirror is /and the distance of the object from the focus is V then the magnification of the mirror will be `("f"/"f−u")`

Reason: Magnification = `"image distance"/ "object distance"` = `(-"v"/"u")`


The power of a lens is +4D. Find the focal length of this lens. An object is placed at a distance of 50 cm from the optical centre of this lens. State the nature and magnification of the image formed by the lens and also draw a ray diagram to justify your answer.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×