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प्रश्न
When 2 moles of an ideal gas are expanded isothermally from a volume of 12.5 L to 15.0 L against constant external pressure of 7 60 mm Hg. Calculate the amount of work done in joule?
विकल्प
- 1924.0 J
- 25.325 J
- 253.25 J
- 190.0 J
MCQ
उत्तर
- 253.25 J
Explanation:
n = 2 mol, V1 = 12.5 L = 12.5 × 10-3 m3, V2 = 15.0 L = 15.0 × 10-3 m3,
P = 760 mm of Hg = 1.013 × 105 Nm-2
W = - Pext (V2 - V1)
= - 1.013 × 105 (15.0 - 12.5)10-3
= - 2.5325 × 105 × 10-3
∴ W = - 253.25 J
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Expression for Pressure-volume (PV) Work
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