Advertisements
Advertisements
प्रश्न
When 22.4 litres of H2 (g) is mixed with 11.2 litres of Cl2 (g), each at 273 K at 1 atm the moles of HCl (g), formed is equal to
विकल्प
2 moles of HCl (g)
0.5 moles of HCl (g)
1.5 moles of HCl (g)
1 mole of HCl (g)
उत्तर
1 mole of HCl (g)
Explanation:
\[\ce{H2_{(g)} + Cl2_{(g)} -> 2HCl_{(g)}}\]
| Content | \[\ce{H2_{(g)}}\] | \[\ce{Cl2_{(g)}}\] | \[\ce{HCl_{(g)}}\] |
| Stoichiometric coefficient | 1 | 1 | 2 |
| No. of moles of reactants allowed to react at 273 K and 1 atm pressure | 22.4 L (1 mol) |
11.2 L (0.5 mol) |
- |
| No. of moles of reactant reacted and product formed | 0.5 | 0.5 | 1 |
| Amount of HCl formed = 1 mol | |||
APPEARS IN
संबंधित प्रश्न
In a reaction \[\ce{x + y + z2 -> xyz2}\] identify the Limiting reagent if any, in the following reaction mixture.
200 atoms of x + 200 atoms of y + 50 molecules of z2
In a reaction \[\ce{x + y + z2 -> xyz2}\] identify the Limiting reagent if any, in the following reaction mixture.
1 mol of x + 1 mol of y + 3 mol of z2
In a reaction \[\ce{x + y + z2 -> xyz2}\] identify the Limiting reagent if any, in the following reaction mixture.
50 atoms of x + 25 atoms of y + 50 molecules of z2
In a reaction \[\ce{x + y + z2 -> xyz2}\] identify the Limiting reagent if any, in the following reaction mixture.
2.5 mol of x + 5 mol of y + 5 mol of z2
