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प्रश्न
When 4 g of iron is burnt to ferric oxide at constant pressure, 29.28 kJ of heat is evolved. What is the enthalpy of formation of ferric oxide?
(Atomic mass of Fe = 56)
विकल्प
−81.98 kJ
−819.8 kJ
−40.99 kJ
+819.8 kJ
MCQ
उत्तर
−819.8 kJ
Explanation:
Required equation is \[\ce{2Fe + 3O2 -> Fe2O3}\]
∴ ∆H = `(-29.28 "kJ" xx 2 "mol" xx 56 "g mol"^-1)/(4 "g")`
= −819.8 kJ
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Enthalpy (H)
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