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प्रश्न
When the observer moves towards a stationary source with velocity V1, the apparent frequency of emitted note is F1. When observer moves away from the source with velocity V1, the apparent frequency is F2. If V is the velocity of sound in air and `"F"_1/"F"_2=2` then `"V"/"V"_1` is equal to ______.
विकल्प
6
3
5
4
MCQ
रिक्त स्थान भरें
उत्तर
When the observer moves towards a stationary source with velocity V1, the apparent frequency of emitted note is F1. When observer moves away from the source with velocity V1, the apparent frequency is F2. If V is the velocity of sound in air and `"F"_1/"F"_2=2` then `"V"/"V"_1` is equal to 3.
Explanation:
`"F"_1=("F"("V"+"V"_1))/"V", "F"_2=("F"("V"-"V"_1))/"V"`
`"F"_1/"F"_2=("V"+"V"_1)/("V"-"V"_1)=2`
solving `"V"/"V"_1=3`
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