Advertisements
Advertisements
प्रश्न
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
उत्तर
Here, P(2) = k
⇒ 23 + 3(2)2 - k(2) + 4 = k
⇒ 8 + 12 - 2k + 4 = k
⇒ 3k = 24
⇒ k = 8
APPEARS IN
संबंधित प्रश्न
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(54m3 + 18m2 − 27m + 5) ; (m − 3)
Polynomials bx2 + x + 5 and bx3 − 2x + 5 are divided by polynomial x - 3 and the remainders are m and n respectively. If m − n = 0 then find the value of b.
Using remainder theorem, find the value of m if the polynomial f(x)= x3 + 5x2 -mx +6 leaves a remainder 2m when divided by (x-1),
Find the values of a and b when the polynomials f(x)= 2x2 -5x +a and g(x)= 2x2 + 5x +b both have a factor (2x+1).
Find ‘a’ if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leaves the same remainder when divided by x + 3.
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x + 3
Check whether p(x) is a multiple of g(x) or not
p(x) = x3 – 5x2 + 4x – 3, g(x) = x – 2