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प्रश्न
Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.
उत्तर
The last element of the actinoid series is Lawrencium (Lr) which has an atomic number of 103. Its electronic configuration is [Rn] 5f146d17s2 and its possible oxidation state is +3.
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संबंधित प्रश्न
Give a reason for the following:
Actinoids show irregularities in their electronic configurations.
Why do actinoids show a wide range of oxidation states?
Write on similarity between the chemistry of lanthanoids and actinoids.
Compare the chemistry of the actinoids with that of lanthanoids with reference to oxidation states
Write four points of distinction between Lanthanoids and Actinoids.
What is the position of actinoids in periodic table ?
How would you account the following :
Highest fluoride of Mn is MnF4 whereas the highest oxide is Mn2O7.
How do you prepare:
Actinoid elements show wide range of oxidation states.
Choose the most correct option.
In which of the following series all the elements are radioactive in nature?
Actinoid series begins at ____________ and ends at ____________.
The actinoid contraction is attributed to the ____________.
The number of unpaired f-electrons in ytterbium (Z = 70) is ____________.
The electronic configuration of Ux+ ion is [Rn]. What is the value of x?
[At. No. of U = 92]
Which among the following actinoids exhibits highest oxidation state +7?
Which of the following properties is NOT of actinoids?
Which of the following oxidation state is common for all lanthanoids?
What is actinoid contraction?
What are actinoids? Give their general electronic configuration.
