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प्रश्न
Which of the following metal halide is more covalent?
विकल्प
\[\ce{SnCl2}\]
\[\ce{PbCl2}\]
\[\ce{SbCl3}\]
\[\ce{SbCl5}\]
MCQ
उत्तर
\[\ce{SbCl5}\]
Explanation:
The metal halide \[\ce{SbCl5}\] is more covalent than the other alternatives. The rule of Fajan can be used to explain it. The polarising power of a cation is proportional to its charge. Antimony (Sb) is in the + 5 oxidation state in \[\ce{SbCl5}\]. It has the most polarising effect. As a result, they have a higher covalent nature.
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