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प्रश्न
Which one of the following homo-diatomic molecule is paramagnetic?
विकल्प
O2
N2
C2
F2
MCQ
उत्तर
O2
Explanation:
For O2 molecule M.O configuration. (16 electrons)
\[\ce{σ 1s^2 σ^∗ 1s^2 σ 2s^2 σ^∗ 2s^2 σ 2p^{2}_z π2p^{2}_x = π2p^{2}_y π^∗ 2P^{1}_y π^∗ 2P_z}\]
For N2 molecule (12 electrons)
\[\ce{σ 1s^2 σ^∗ ls^2 σ 2s^2 σ^∗ 2s^2 π2p^{2}_x = π2p^{2}_y}\]
For F2 molecule (18 electrons)
\[\ce{σ 1s^2 σ^∗ ls^2 σ 2s^2 σ^∗ 2s^2 σ2p^{2}_r π2p^{2}_x = π2p^{2}_y π^∗ 2p^{2}_x = π^∗ 2p^{2}_y σ^* 2p_z}\]
O2 molecule is paramagnetic with 2 unpaired electrons in π*2px and π*2py orbitals.
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