Question

Which one of the following orders is CORRECT in case of energy of the given subshells?

P: n = 4; l = 3

Q: n = 5; I = 1

R: n = 5; l = 0

S: n = 4; l = 2

विकल्प

• S < R < Q < P

• R < P < S < Q

• P < S < R < Q

• R < S < Q < P

Answer 1

R < S < Q < P

Explanation:

Higher the value of (n + l), the greater is the energy. For the same value of (n + l), higher the value of 'n', the greater is the energy.

P: n = 4; l = 3; (n + l) = 7

Q: n = 5; I = 1; (n + l) = 6

R: n = 5; l = 0; (n + l) = 5

S: n = 4; l = 2; (n + l) = 6

Thus, the order of energy of the given subshells is, R < S < Q < P