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प्रश्न
Which quantity out of ∆rG and ∆rGΘ will be zero at equilibrium?
उत्तर
Gibbs energy for a reaction in which all reactants and products are in standard state. ΔrGΘ is related to the equilibrium constant of the reaction as follows
ΔrG = ArGΘ + RT In K
At equilibrium, 0 = ΔrGΘ + RT In A – ({ΔrG = 0) or ΔrGΘ = – RT ln K
ΔrGΘ = 0 when K= 1
For all other values of K, ArGΘ will be non-zero.
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| ∆ (Parameters) \[\ce{∆_rH^Θ, ∆_rS^Θ, ∆_rG^Θ}\] |
Description |
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| (iii) \[\ce{– + –}\] | (c) Non-spontaneous at all temperatures |
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