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प्रश्न
While measuring the length of a rod with a vernier callipers, below shows the position of its scales. What is the length of the rod?
उत्तर
L.C. of vernier callipers = 0.01 cm
In the shown scale,
Main scale reading = 3.3 cm
The 6th vernier division coincides with an m.s.d.
Therefore, vernier scale reading = 6 × 0.01 cm = 0.06 cm
Total reading = M.S.R. + V.S.R.
= 3.3 + 0.06
= 3.36 cm
संबंधित प्रश्न
Fig., below shows the reading obtained while measuring the diameter of a wire with a screw gauge. The screw advances by 1 division on the main scale when circular head is rotated once.
Find:
(i) Pitch of the screw gauge,
(ii) Least count of the screw gauge and
(iii) The diameter of the wire.
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
In figure for vernier callipers, calculate the length recorded.
State the formula for determining least count for a vernier callipers.
State the formula for calculating length if:
Number of vernier scale division coinciding with the main scale and number of division of main scale on the left-hand side of zero of vernier scale is known.
What is the function of ratchet in the screw gauge?
How do you account for negative zero error, for calculating the correct diameter of wires?
What is the least count in the case of the following instrument?
Metre scale
What is meant by the pitch of a screw gauge? The pitch of a screw is 1 mm.
Find the reading of the instrument shown in the following figure.
