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प्रश्न
Write a balanced chemical equation of the following reaction and also classify them.
Lead acetate solution is treated with dilute hydrochloric acid to form lead chloride and acetic acid solution.
उत्तर
`"Pb"("CH"_3"COO")_2("s") + 2"HCl" ("aq") -> "PbCl"_2("s") + "CH"_3"COOH"("aq")` : Double displacement reaction
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संबंधित प्रश्न
Balance the following equation. Also name the products formed.
`Na + H_2 O → Na OH + H_2`
Balance the following equation. Also name the products formed.
`CO + O_2 → CO_2`
Balance the following important equation:
Na2CO3 + HCl → NaCl + H2O + CO2
Balance the following important equation:
\[\ce{Pb3O4 + HCl -> PbCl2 + H2O + Cl2}\]
Balance the following important equation:
NH3 + O2 → N2 + H2O (burning of NH3)
Balance the following important equation:
S + HNO3 (conc.) → H2SO4 + H2O + NO2
In a chemical reaction between sulphuric acid and barium chloride solution the white precipitates formed are of:
Write the balanced chemical equations for the following reactions and identify the type of reaction in each case.
- Iron (III) oxide reacts with aluminum and gives molten iron and aluminum oxide.
- Magnesium ribbon is burnt in an atmosphere of nitrogen gas to form solid magnesium nitride.
- Chlorine gas is passed in an aqueous potassium iodide solution to form potassium chloride solution and solid iodine.
- Ethanol is burnt in air to form carbon dioxide, water and releases heat.
A magnesium ribbon is burnt in oxygen to give a white compound ‘X’ accompanied by emission of light. If the burning ribbon is now placed in an atmosphere of nitrogen, it continues to burn and forms a compound ‘Y’.
- Write the chemical formulae of X and Y.
- Write a balanced chemical equations when X and Y are dissolved in water.
Balance the following equation.
\[\ce{Calcium chloride + Sulphuric acid -> Calcium sulphate + Hydrogen chloride}\]
