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Write Clemmenson's reduction reaction of propanone. - Chemistry

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प्रश्न

Write Clemmenson's reduction reaction of propanone.

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उत्तर

Explanation:

Clemmensen’s reduction converts a ketone or aldehyde to the corresponding alkane using zinc amalgam (Zn-Hg) and concentrated hydrochloric acid (HCl).

In this case, propanone \[\ce{(CH3COCH3)}\] is reduced to propane \[\ce{(CH3CH2CH3)}\].

Reaction:

\[\ce{CH3COCH3 ->[HCl][Zn] CH3CH2CH3}\]

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