Advertisements
Advertisements
प्रश्न
Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.
उत्तर
The general formula for the homologous series whose first member is ethyne is CnH2n - 2.
The two consecutive members (2nd and 3rd) of this series are:
a. CH3C≡CH (Propyne); where n is 3
b. CH3CH2C≡CH(1-Butyne) or CH3C≡CCH3 (2-Butyne); where n is 4
The molecular formulae are C3H4 and C4H6, respectively.
APPEARS IN
संबंधित प्रश्न
Write the next homologue of the following: C4H6
Write the molecular formula of first two members of homologous series having functional group -Cl.
Write the molecular formula of first two members of homologous series having functional group – OH
Give the molecular formula of one homologue of each of the following:
C2H6
Write the molecular formula of the third member of the homologous series of carbon compounds with general formula CnHO2n+1OH.
The number of carbon atoms present in the molecule of fifth member of the homologous series of alkynes is:
(a) four
(b) five
(c) six
(d) seven
Give the structure of the second member of the alcohol group
Give three points to differentiate between saturated and unsaturated
hydrocarbons.
Two statements are given - one labeled Assertion (A) and the other labeled Reason (R).
Assertion (A): In a homologous series of alcohols, the formula for the second member is C2H5OH and the third member is C3H7OH.
Reason (R): The difference between the molecular masses of the two consecutive members of a homologous series is 144.
Successive members of a homologous series vary by how many atomic mass unit?
