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Write the expression for relative lowering of vapour pressure. - Chemistry

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प्रश्न

Write the expression for relative lowering of vapour pressure.

एक पंक्ति में उत्तर

उत्तर

Relative lowering of vapour pressure = `(Delta "P")/"P"_1^0 = ("P"_1^0 - "P"_1)/"P"_1^0 = "x"_2`

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Vapour Pressure Lowering
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अध्याय 2: Solutions - Very short answer questions

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एससीईआरटी महाराष्ट्र Chemistry [English] 12 Standard HSC
अध्याय 2 Solutions
Very short answer questions | Q 4

संबंधित प्रश्न

Choose the most correct option.

Pressure cooker reduces cooking time for food because _______.


Answer the following.

How vapour pressure lowering is related to a rise in the boiling point of solution?


Answer the following.

Why vapour pressure of a solvent is lowered by dissolving a nonvolatile solute into it?


The following solution/solvent has maximum vapour pressure _______.


According to Raoult’s law, relative lowering of vapour pressure of solution containing dissolved nonvolatile solute _______.


The vapour pressure of a pure liquid is 0.043 bar at a certain temperature. When a nonvolatile solute is dissolved into it, the vapour pressure of the solution is found to be 0.041 bar. What is the relative lowering of vapour pressure?


For a very dilute solution, the osmotic pressure is given by π = n2RT/V where V is the volume in L containing n2 moles of nonvolatile solute. Establish the equation for molar mass of solute.


Give two points to explain why vapour pressure of solvent is lowered by dissolving nonvolatile solute into it.


Which of the following is CORRECT for a solution containing non-volatile solute in it?


Which of the following is CORRECT statement?


The vapour pressure of pure benzene (molar mass 78 g/mol) at a certain temperature is 640 mm Hg. A nonvolatile solute of mass 2.315 g is added to 40 g of benzene. The vapour pressure of the solution is 600 mm Hg. The molar mass of solute is ____________.


At a constant volume, a quantity of an ideal gas has a pressure of 700 mm Hg at 300 K. At what pressure, the temperature will be halved?


The vapour pressure of water at 20°C is 17 mm Hg. The vapour pressure of solution containing 2.8 g urea in 50 g of water is ____________.


Which of the following changes will cause increase in vapour pressure of 1 molal aqueous KI solution at same temperature?


What will be the molar mass of solute if vapour pressure of pure benzene is 450 mm Hg when 1.5 g of non-volatile solute is added to 30 g of benzene?
(Vapour pressure of solution= 400 mm Hg, Atomic mass C = 12, H = 1)


Relative lowering in vapour pressure depends on _______.


38.4 g of unknown substance (molar mass 384 g mol-1) and 116 g of acetone is used to prepare a solution at 313 K. If vapour pressure of pure acetone (molar mass 58 g mol-1) is 0.842 atmosphere, what is the vapour pressure of solution?


12 g of a nonvolatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0.1. The molecular mass of the solute is ______.


The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent its vapour pressure drops to 0.6 atm. the mole fraction of B in the solution is ______.


Which of the following solutions will have the maximum lowering of vapour pressure at 300 K?


The vapour pressure of 100 g of water reduces from 17.53 mm to 17.22 mm when 17.10 g, of substance X is dissolved in it. Substance X can be ______.


Calculate the mole fraction of solute, if the vapour pressure of pure benzene at a certain temperature is 640 mmHg and the vapour pressure of a solution of a solute in benzene is 600 mmHg.


State and explain Raoult's law for the solution of non-volatile solutes.


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