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प्रश्न
You are provided with the following chemicals:
NaOH, Na2CO3, H2O, Zn(OH)2, CO2, HCI, Fe, H2SO4, CI2, Zn.
Using the suitable chemicals from the given list only, state briefly how you would prepare sodium sulphate.
उत्तर
Sodium sulphate can be prepared by neutralising NaOH with H2SO4.
\[\ce{2NaOH + H2SO4 -> \underset{sulphate}{\underset{Sodium}{Na2SO4}} + 2H2O}\]
संबंधित प्रश्न
How is the following salt prepared:
Sodium nitrate from sodium hydroxide.
How many salts can be obtained from ortho phosphoric acid? Is there any difference in the salts formed by the acid?
State how would you prepare copper (II) oxide from
copper sulphate
Give equation to prepare the following as directed
NaHCO3 from Na2CO3
Write the balanced equation for the preparation of the following compounds, starting from iron and other substance:
Iron (II) sulphide
Give the equation for the preparation of the following salt from the starting material given.
Copper sulphate from copper (II) oxide
Explain why Anhydrous FeCl3 cannot be prepared by heating hydrated iron (III) chloride.
Match the salts underlined in Column A with the most suitable method of preparation given in Column B.
Column A | Column B | ||
(a) | \[\ce{ZnCl2 \text{from} Zn}\] | 1. | Precipitation |
(b) | \[\ce{KNO3 \text{from} KOH}\]. | 2. | Direct combination |
(c) | \[\ce{CaCO3 \text{from} CaCl2}\]. | 3. | Displacement reaction |
4. | Neutralization |
The following is a list of methods for the preparation of salts.
A – direct combination of two elements.
B – reaction of a dilute acid with a metal.
C – reaction of a dilute acid with an insoluble base.
D – titration of a dilute acid with a solution of soluble base.
E – reaction of two solutions of salts to form a precipitate.
Choose from the above list A to E, the best method of preparing the following salt by giving a suitable equation in the following case:
Copper sulphate.
Select the word/s given which are required to correctly complete the blanks.
If a piece of magnesium was put into a solution M, ______ gas would be evolved.