Question

0.05 F electricity is passed through CuSO₄ solution. Calculate the mass of Cu produced at cathode? (molar  mass of Cu = 63.5 g mol^-1)

पर्याय

• 3.17 g

• 2.54 g

• 0.795 g

• 1.59 g

Answer 1

1.59 g

Explanation:

Equivalent mass of copper = `"Atomic mass"/"Valency"`

`= 63.5/2 = 31.75`

Amount of copper deposited by 0.05 F

`= 0.05 xx 31.75`

= 1.5875 ≈ 1.59 g