Question

10 ml of H₂O₂ solution when reacted with KI solution produced 0.5 g of iodine. The percentage of purity of H₂O₂ (by volume) is ______%.

पर्याय

• 0.669

• 0.795

• 0.826

• 0.936

Answer 1

10 ml of H₂O₂ solution when reacted with KI solution produced 0.5 g of iodine. The percentage of purity of H₂O₂ (by volume) is 0.669%.

Explanation:

Equation of H₂O₂ = Equation of I₂

(10 × 10^–3) × N = `0.5/127`

⇒ N = 0.3937

∴ Volume strength of H₂O₂ = N × 5.6

= 0.3937 × 5.6

= 2.2 Volume

Equation of H₂O₂ = Equation of I₂

`w/(34//2) = 0.5/127`

`w` = 0.0669 g

∴ % of purity (by volume) = `0.0669/10 xx 100` = 0.669%