Question

120 g of an ideal gas of molecular weight 40 g mol⁻¹ are confined to a volume of 20 L at 400 K.
Using R = 0.0821 L atm K⁻¹ mol⁻¹, the pressure of the gas is ______.

पर्याय

• 4.90 atm

• 4.92 atm

• 5.02 atm

• 4.96 atm

Answer 1

120 g of an ideal gas of molecular weight 40 g mol⁻¹ are confined to a volume of 20 L at 400 K.
Using R = 0.0821 L atm K⁻¹ mol⁻¹, the pressure of the gas is 4.92 atm.

Explanation:

PV = RT, PV = `"w"/"M" "RT"`,

20 P = `120/40 xx 0.0821 xx 400`

or P = 4.92 atm