मराठी

24 Cc Marsh Gas (Ch4) Was Mixed with 106 Cc Oxygen and Then Exploded. on Cooling the Volume of the Mixture Became 82 Cc, of Which, 58 Cc Was Unchanged Oxygen. Which Law Does this Experiment - Chemistry

Advertisements
Advertisements

प्रश्न

24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. On cooling the volume of the mixture became 82 cc, of which, 58 cc was unchanged oxygen. Which law does this experiment support? Explain with calculations.

संख्यात्मक

उत्तर

This experiment supports Gay Lussac's law of combining volumes.

According to Gay lussac's law, the volumes of gases reacting should be in a simple ratio.

\[\ce{CH4 + 2O2 → CO2 + 2H2O}\]

1V         2V            1V        0V

24 cc     48 cc        24 cc

1 vol. of CH4 requires O2 = 2 vols.

∴ 24 cc of CH4 requires O2 = 2 x 24 = 48 cc

Similarly, 24 cc of CH4 produce CO2 = 24 cc

∴ Vol. of O2 unused = 106 − 48 = 45 cc

∴ Vol. of mixture on cooling = unused oxygen + CO2 formed

= 58 + 24 

= 82 cc

shaalaa.com
Fundamental Laws of Gases - Gay Lussac’s Law of Combining Volumes
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole concept and Stoichiometry - Exercise 5A [पृष्ठ ७५]

APPEARS IN

सेलिना Concise Chemistry [English] Class 10 ICSE
पाठ 5 Mole concept and Stoichiometry
Exercise 5A | Q 5 | पृष्ठ ७५

संबंधित प्रश्‍न

Propane burns in air according to the following equation: 

C3H8 + 5O2 → 3CO2 + 4H2O

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


What volume of oxygen would be required for complete combustion of 100L of ethane according to the following equation?
2C2H6 + 7O2 → 4CO2 + 6H2O


What volume of oxygen would be required to burn completely 400 ml of acetylene [C2H2]? Also calculate the volume of carbon dioxide formed.

\[\ce{2C2H2 + 5H2O -> 4CO2 + 2H2O(l)}\]


1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of carbon dioxide formed:

\[\ce{2C2H6 + 7O2  -> 4CO2 + 6H2O}\]


What volume of propane is burnt for every 500 cm3 of air used in the reaction under the same conditions? (assuming oxygen is `1/5`th of air)

\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]


Ammonia may be oxidised to nitrogen monoxide in the presence of a catalyst according to the following equation.

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]

If 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and pressure?


LPG has 60% propane and 40% butane: 10 litres of this mixture is burnt. Calculate the volume of carbon dioxide added to atmosphere.

\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]

\[\ce{2C4H10 + 13O2 → 8CO2 + 10H2O}\]


112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Write a balanced equation for this reaction.


The reaction: \[\ce{4N2O + CH4 -> CO2 + 2H2O + 4N2}\] takes place in the gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N2O) required to give 150 cm3 of steam.


112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate composition of the resulting mixture.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×