Advertisements
Advertisements
प्रश्न
250 g of water at 30 °C is present in a copper vessel of mass 50 g. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5 °C.
Specific latent heat of fusion of ice = 336 × 103 J kg-1
Specific heat capacity of copper vessel = 400 J kg-1 °C-1
Specific heat capacity of water = 4200 J kg-1 °C-1.
उत्तर
Given: water = 250 gm = 30 °C
mass of vessel = 50 gm
Final temperature = 5 °C
By the principle of calorimeter.
Heat given = Heat taken,
Let mass of ice = m gm
250 × 4.2 × (30 - 5) + 50 × 0.4 × 25 = m × 336 + m × 4.2 × 5
26250 + 500 = 336 m + 21 m
26750 = 357 m
m = 74.9 gm.
APPEARS IN
संबंधित प्रश्न
What is a calorimeter?
200 g mass of certain metal of 83°C is immersed in 300 g of water at 30°C the final temperature
is 33°C. Calculate the specific heat capacity of the metal Assume that the specific heat capacity
of water is `4.2 J g^-1K^-1`
Fill in the following blank using suitable word:
1 cal = .......... J
Fill in the following blank using suitable word:
SI unit of specific heat is ..........
Name two factors on which the heat energy librated by a body on cooling depends.
Out of the three metals A, B and C of specific heat 900 J kg-1 °C-1, 380 J kg-1 °C-1 and 460 J kg-1 °C-1 respectively, which will you prefer for calorimeter? Given reason.
Why does the heat supplied to a substance during its change of state not cause any rise in its temperature?
State two impacts of global warming on the life on earth.
Explain briefly, how you would determine the specific heat capacity of a liquid?
Calculate the heat energy that will be released when 5.0 kg of steam at 100°C condenses to form water at 100°C. Express your answer in S.I. unit. (Specific latent heat of vaporization of steam is 2268 kj/kg.)
