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प्रश्न
32P beta-decays to 32S. Find the sum of the energy of the antineutrino and the kinetic energy of the β-particle. Neglect the recoil of the daughter nucleus. Atomic mass of 32P = 31.974 u and that of 32S = 31.972 u.
उत्तर
Given:
Atomic mass of 32P, m(32P) = 31.974 u
Atomic mass of 32S, m(32S) = 31.972 u
Reaction :
`P^32 → S^32 + _1V^0 + _-1beta^0`
Energy of antineutrino and β-particle, E = `[m(""^32P) - m(""^32S)]c^2`
= `(31.974 "u" - 31.972 "u")c^2`
= `0.002 xx 931 = 1.862 "MeV"`
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