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प्रश्न
3.36 M sulphuric acid solution is 29% H2SO4 calculate the density of the solution.
पर्याय
1.00 gm–1
1.22 gm–1
1.51 gm–1
2.00 gm–1
MCQ
उत्तर
1.22 gm–1
Explanation:
Calculation of the mass of solution.
Mass of H2SO4 in 3.6 m solution = 3.6 mol × 90 g mol–1
29% H2SO4 means that = 352.8 g
29 g of H2SO4 are present in solution = 100 g
B = 2.8 g of H2SO4 are present in solution = `(100 g)/(29 g) xx 352.8 g` = 1216.5 g
Density of the solution = `"Mass of solution"/"Volume of solution"`
= `1216.5/(100 mL)`
= 1.22 gm–1
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