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प्रश्न
3.795 g of sulphur is dissolved in 100g of CS2. This solution boils at 319.81 K. What is the molecular formula of sulphur in solution? The boiling point of CS2 is 319.45 K. (Given that Kb for CS2 = 2.42 K kg mol-1 and atomic mass of S = 32)
उत्तर
Given:
Mass of sulphur = W2 = 3.795 g = 3.795 x 10-3 kg
Mass of solvent = W1 = 100 g = 100 x 10-3 kg
Boiling point of solution = Tb = 319.81 K
Boiling point of pure solvent = `T_b^@` = 319.45 K
Molal elevation constant = Kb = 2.42 K kg mol-1
Atomic mass of sulphur = 32
To find: Molecular formula of sulphur in solution
`n = "Molar massof sulphur"/"Atomic mass of sulphur"`
∴ `n = (255.1)/32`
= 7.97 ≈ 8
∴ Molecular formula of sulphur in CS2 = S8
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संबंधित प्रश्न
The atomicity of sulphur in orthorhombic sulphur is______________ .
(a) 8
(b) 6
(c) 4
(d) 2
Write the electronic configuration of the following elements:
Sulphur (Z = 16)
Give reasons Dioxygen is a gas while Sulphur is a solid at room temperature.
How do you prepare:
Na2Cr2O7 from Na2CrO4?
Give reasons for the following:
Sulphur in vapour state shows paramagnetic behaviour.
Assertion: Both rhombic and monoclinic sulphur exist as S8 but oxygen exists as O2.
Reason: Oxygen forms pπ – pπ multiple bonds due to small size and small bond length but pπ – pπ bonding is not possible in sulphur.
α and β forms of sulphur are at equilibrium at a temperature known as ______.
Name two allotropes of sulphur.
Draw structure of sulphur molecule (Rhombic sulphur). Mention bond angle and bond length.
