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प्रश्न
`3x^2x-1=0`
उत्तर
We Write, `-2x=-3x+x as 3x^2xx(-1)=-3x^2=(-3x)xx x`
∴` 3x^2-2x-1=0`
⇒`3x^2-3x+x-1=0`
⇒`3x(x-1)+1(x-1)=0`
⇒`(x-1)(3x+1)=0`
⇒`x-1=0 or 3x+1=0`
`⇒x=1 or x=-1/3`
Hence, the roots of the given equation are 1 and -1/3
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