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प्रश्न
4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10−1. The value of x is ______. (Rounded-off to the nearest integer)
पर्याय
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MCQ
रिकाम्या जागा भरा
उत्तर
4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10−1. The value of x is 2.
Explanation:
Moles of A = `"Weight"/"MW"`
= `4.5/90`
= `1/20`
= 0.05
Volume (Lit) = `250/1000` = 0.250 lit
Molarity (M) = `"Mole"/(("Lit")"volume")`
= `0.05/0.250`
= 0.2
= 2 × 10−1 `"mol"/"Lit"`
x = 2
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