Advertisements
Advertisements
प्रश्न
9 is subtracted from the product of p and 4, the result is 11. The value of p is ______.
उत्तर
9 is subtracted from the product of p and 4, the result is 11. The value of p is 5.
Explanation:
Given, 9 is subtracted from the product of p and 4.
Then, 4p – 9 = 11
⇒ 4p = 11 + 9 ...[Transposing –9 to RHS]
⇒ 4p = 20
⇒ `(4p)/4 = 20/4` ...[Dividing both sides by 4]
∴ p = 5
Hence, the value of p is 5.
APPEARS IN
संबंधित प्रश्न
The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?
The base of an isosceles triangle is `4/3` cm. The perimeter of the triangle is `4 2/15` cm. What is the length of either of the remaining equal sides?
Two numbers differ by 40, when each number is increased by 8, the bigger becomes thrice the lesser number. If one number is x, then the other number is (40 – x).
Solve the following:
`(y - (4 - 3y))/(2y - (3 + 4y)) = 1/5`
Solve the following:
`x/5 = (x - 1)/6`
Solve the following:
0.4(3x – 1) = 0.5x + 1
Solve the following:
4t – 3 – (3t + 1) = 5t – 4
Solve the following:
`(3t + 5)/4 - 1 = (4t - 3)/5`
Solve the following:
`(9 - 3y)/(1 - 9y) = 8/5`
Solve the following:
`(3x + 2)/(2x - 3) = - 3/4`