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प्रश्न
A 100 V battery is connected to the electric network as shown. If the power consumed in the 2 Ω resistor is 200 W, determine the power dissipated in the 5 Ω resistor.
उत्तर
Total current\[I = \sqrt{\frac{P}{R}} = \sqrt{\frac{200}{2}} = 10A\]
Equivalent circuit:
Potential difference across AB = potential difference across CD
\[\Rightarrow I_1 R_1 = I_2 R_2 \]
\[ \Rightarrow 10 I_1 - 40 I_2 = 0\]
\[ \Rightarrow I_1 - 4 I_2 = 0 . . . (1)\]
\[ \Rightarrow I_1 + I_2 = I\]
\[ \Rightarrow I_1 + I_2 = 10 . . . (2)\]
\[ \Rightarrow I_1 = 8A\]
Power dissipated in the 5 Ω resistor = 5 \[\times\] (current through 5 Ω resistor)2
∴ P = 320 W
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