Advertisements
Advertisements
प्रश्न
A 12 liter solution is `33(1)/(3)`% acid. How much water must be added to get the solution having 20% acid?
उत्तर
Let x be the water added
then,
12(33.33%) = 20%(x + 12)
⇒ 12 x 0.3333 = 0.2(x + 12)
⇒ 3.999 = 0.2x + 2.4
⇒ 0.2x = 1.596
⇒ x = 7.95It = 8It
Approximately, 8 litres of water nust be added.
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
3a - 4 = 2(4 - a)
Solve the following equation:
`5/8 "n" = 20`
Solve: `"2x"/3 + "x"/2 - "3x"/4 = 1`
Solve: `("x" + 4)/2 + "x"/3 = 7`
Solve the following equation for the unknown: `x/(2) + x/(4) + x/(8)` = 7
If `(2)/"m" xx 1(1)/(5) = (3)/(7) "of" 2(1)/(2)`, find the value of 'm'.
Solve the following equations: a(x - b) -b (x - a) = a2 - b2
The sum of the squares of two consecutive odd natural numbers is 650. Find the two numbers.
In a two digit number, the ratio of the digits at the unit's place and the ten's place is 3:2. If the digits are reversed, the resulting number is 27 more than the original number. Find the two digit number.
A boy played 100 games, gaining Rs 50 on each game that he won, and losing Rs 20 for each game that he lost. If on the whole he gained Rs 800, find the number of games that he won.
