मराठी

A 5.5 m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4 m. Find the distance between the wall and the foot of the ladder. - Mathematics

Advertisements
Advertisements

प्रश्न

A 5.5 m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4 m. Find the distance between the wall and the foot of the ladder.

तक्ता
बेरीज

उत्तर

Let the distance between the wall and the foot of the ladder be x m

In right-angled ΔABC, by using Pythagoras theorem, we get

BC2 = AB2 + AC2

⇒ (5.5)2 = x2 + (4.4)2

⇒ x2 = (5.5)2 – (4.4)2

⇒ x2 = 30.25 – 19.36

 ⇒ x2 = 10.89

⇒ x = `sqrt(10.89)`

  3.3
3 `bar10.bar89`
  9
63 189
  189
  0

∴  x = 3.3 m

Hence, the distance between the wall and the foot of the ladder is 3.3 m.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Square-Square Root and Cube-Cube Root - Exercise [पृष्ठ ९६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
पाठ 3 Square-Square Root and Cube-Cube Root
Exercise | Q 128. | पृष्ठ ९६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

What will be the units digit of the square of the following number? 

 4583 


What will be the units digit of the square of the following number? 

 78367 


Which of the following triplet  pythagorean? 

(12, 35, 38) 


Observe the following pattern 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) = \frac{2 \times 3 \times 4}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) = \frac{3 \times 4 \times 5}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) + \left( 4 \times 5 \right) = \frac{4 \times 5 \times 6}{3}\] 

and find the value of(1 × 2) + (2 × 3) + (3 × 4) + (4 × 5) + (5 × 6)


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

52 + 62 + 72 + 82 + 92 + 102 + 112 + 122

 

 


Find the square of the following number: 

503


Find a Pythagorean triplet in which one member is 12.


The hypotenuse of a right triangle with its legs of lengths 3x × 4x is ______.


For every natural number m, (2m – 1, 2m2 – 2m, 2m2 – 2m + 1) is a pythagorean triplet.


Find the length of the side of a square if the length of its diagonal is 10 cm.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×