Question

A and B are two points in an electric field. If the work done in carrying 4.0C of electric charge from A to B is 16.0 J, the potential difference between A and B is:

पर्याय

• zero

• 2.0 V

• 4.0 V

• 16.0 V

Answer 1

4.0 V

Explanation:

Since W_A→B = q(V_B − V_A)

⇒ V_B − V_A = `16/4` = 4 V