Question

A battery of EMF 10V sets up a current of 1A when connected across a resistor of 8Ω. If the resistor is shunted by another 8Ω resistor, what would be the current in the circuit? (in A)

पर्याय

• 1.50

• 1.57

• 1.67

• 1.53

Answer 1

1.67

Explanation:

I₁ = 1 = `"E"/"R + r" = 10/(8+"r")`  ⇒ r = 2Ω

I₂ = `"E"/((8  "//"  8)+2) = 10/6`

= 1.67 A