Advertisements
Advertisements
प्रश्न
A black compound of manganese reacts with a halogen acid to give greenish-yellow gas. When excess of this gas reacts with \[\ce{NH3}\] an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from ______.
पर्याय
– 3 to +3
– 3 to 0
– 3 to +5
0 to – 3
उत्तर
A black compound of manganese reacts with a halogen acid to give greenish-yellow gas. When excess of this gas reacts with \[\ce{NH3}\] an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from – 3 to +3.
Explanation:
\[\ce{\underset{(Black)}{Mno2} + 4HCl -> MnCl2 + \underset{(Greenish yellow gas)}{2H2O} + Cl}\]
When excess of \[\ce{Cl2}\] reacts with \[\ce{NH3}\] the products are \[\ce{NCl3}\] and \[\ce{HCl}\].
\[\ce{NH3 + 3Cl2 -> NCl3 + 3HCl}\]
\[\ce{O.S. (-3) O.S. (+3)}\]
APPEARS IN
संबंधित प्रश्न
Account for the following :
Fluorine forms only one oxoacid HOF
Draw the structures of the following:
(1) HClO4
(2) H3PO3
Draw the structures of the HClO3.
Account for the following :
HClO4 is a stronger acid than HClO.
The increasing order of reducing power of the halogen acids is:
Which one of the following order is correct for the bond dissociation enthalpy of halogen molecule?
Assertion: HI cannot be prepared by the reaction of KI with concentrated H2SO4.
Reason: HI has the lowest H-X bond strength among halogen acids.
Explain why the stability of oxoacids of chlorine increases in the order given below:
\[\ce{HClO < HClO2 < HClO3 < HClO4}\]
Which halogen forms an oxyacid that contains the halogen atom in tripositive oxidation state?
Which among the following factors is the most important in making fluorine, the strongest oxidizing halogen?
