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प्रश्न
A black rectangular surface of area 'A' emits energy 'E' per second at 27 °C. If length and breadth are reduced to `1/2` of initial value and 2 temperature is raised to 327 °C then energy emitted per second becomes ______.
पर्याय
`"E"/4`
`4"E"`
`(10"E")/9`
`(16"E")/9`
MCQ
रिकाम्या जागा भरा
उत्तर
A black rectangular surface of area 'A' emits energy 'E' per second at 27 °C. If length and breadth are reduced to `1/2` of initial value and 2 temperature is raised to 327 °C then energy emitted per second becomes 4E.
Explanation:
`"E"_2/"E"_1 =("A"_2/"A"_1)("T"_2/"T"_1)^4=((l/2xxb/2)/(lxxb))((327+273)/(27+273))^4`
=`(1/4)(600/300)^4`
∴ `"E"_2/"E"_1=1/4xx(16)`
∴`"E"_2= 4"E".....(∵"E"_1="E")`
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Stefan-boltzmann Law of Radiation
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