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प्रश्न
A body of mass m performs linear S.H.M. given by equation, x = P sin cot + Q sin`(omega"t" + pi/2)`. The total energy of the particle at any instant is ______.
पर्याय
`1/2 "m"omega ("P"^2 + "Q"^2)`
`1/2 "m"omega^2//"PQ"`
`1/2 "m"omega^2 "PQ"`
`1/2 "m"omega^2 "P"^2 "Q"^2`
MCQ
रिकाम्या जागा भरा
उत्तर
A body of mass m performs linear S.H.M. given by equation, x = P sin cot + Q sin`(omega"t" + pi/2)`. The total energy of the particle at any instant is `underline(1/2 "m"omega ("P"^2 + "Q"^2))`.
Explanation:
x = P sin cot + Q sin`(omega"t" + pi/2)`
= P sin ωt + Q cos ωt
Let P = A cos θ Q = A sin θ
∴ P2 + Q2 = A2
∴ x = A sin (ωt + θ)
`"E"_"total" = 1/2 "m"omega^2 "A"^2`
`= 1/2 "m"omega^2 ("P"^2 + "Q"^2)`
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