Advertisements
Advertisements
प्रश्न
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears a number divisible by 5.
उत्तर
Let E3 be the event of getting a number divisible by 5.
Discs bearing numbers divisible by 5 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85 and 90.
Number of discs bearing a number divisible by 5 = 18
∴ P(getting a number divisible by 5) = P(E3) =`("Number of outcomes favourable to" E_3)/"Number of all possibles outcomes"`
`= 18/90 = 1/5`
Thus, the probability that the disc bears a number divisible by 5 is `1/5`.
APPEARS IN
संबंधित प्रश्न
Peter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die and squares the number obtained. Who has the better chance to get the number 25
Two dice are rolled together. Find the probability of getting such numbers on two dice whose product is a perfect square.
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears a two-digit number,
One card is drawn from a well-shuffled deck of 52 cards. Find the probability of drawing a 9 of a black suit.
A card is drawn at random from a well-shuffled deck of 52 cards. Find the probability of getting a red ace.
Cards bearing numbers 1, 3, 5, .... , 35 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card bearing a number divisible by 3 and 5.
In a lottery, there are 6 prizes and 24 blanks. What is the probability of not getting a prize?
The probability expressed as a percentage of a particular occurrence can never be ______.
Two coins are tossed simultaneously. What is the probability of getting at most one tail?
Two coins are tossed simultaneously. What is the probability of getting a head and a tail?
