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प्रश्न
उत्तर
Total number of discs = n(S) = 90
Let B be the event of getting a number divisible by 5.
Numbers divisible by 5 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85 and 90.
The probability that it bears a number divisible by 5 and greater than 50 is 55, 60, 65, 70, 75, 80, 85 and 90.
∴ n (B) = 8
∴ P (B) = `("n"("B"))/("n"("S")) = 8/90 ~~ 4/45`
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