Question

A boy records that 4000 joules of work are required to transfer 10 coulombs of charge between two points of a resistor of 50 Ω. The current passing through it is:

पर्याय

• 2 A

• 4 A

• 8 A

• 16 A

Answer 1

8 A

Explanation:

Work done in transferring the charge

W = qV = qlR ……..(V = IR)

⇒ I = `"V"/"qR" = 4000/(10 xx 50)` = 8 A