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प्रश्न
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
The Deceleration.
उत्तर
Deceleration a = ( v - u )/t = ( o - 30 )/ 20 = -1.5 ms-2
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संबंधित प्रश्न
Figure shows the velocity-time graphs for two cars A and B moving in the same direction. Which car has greater acceleration? Give reasons to your answer.
The velocity-time graph for a uniformly retarded body is a straight line inclined to the time axis with an obtuse angle. How is retardation calculated from the velocity-time graph?
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
The acceleration.
Assertion: The accelerated motion of an object may be due to change in magnitude of velocity or direction or both of them.
Reason: Acceleration can be produced only by change in magnitude of the velocity. It does not depend the direction.
The slope of a velocity-time graph gives ______.
When a body starts from rest, the acceleration of the body after 2 seconds in ______ of its displacement.
If a body starts from rest, what can be said about the acceleration of the body?
The value of acceleration for a body at rest is ______.
Acceleration is a scalar.
Assertion: When a body is subjected to a uniform acceleration, it is always moving in a straight line.
Reason: Motion may be straight-line motion or circular motion.
