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प्रश्न
A charge of 400C flows through a conductor for 13 minutes and 20 seconds. Find the magnitude of the current flowing through the conductor.
संख्यात्मक
उत्तर
Q = 400C
t = 13 min and 20s = 13 × 60 + 20
= 780 + 20
= 800s
Current I = \(\frac{Q}{t}=\frac{400}{800}=0.5 \mathrm{A}\)
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