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प्रश्न
A common emitter amplifier is designed with n-p-n transistor (α = 0.99). The input impedance is 1 kΩ and the load is 10 kΩ. The voltage gain will be ______
पर्याय
9.9
99
990
9900
MCQ
रिकाम्या जागा भरा
उत्तर
A common emitter amplifier is designed with n-p-n transistor (α = 0.99). The input impedance is 1 kΩ and the load is 10 kΩ. The voltage gain will be 990.
Explanation:
Voltage gain = β x Resistance gain
β = `alpha/(1 - alpha) = 0.99/((1 - 0.99)) = 99`
∴ Resistance gain = `(10 xx 10^3)/(10^3) = 10`
⇒ Voltage gain = 99 × 10 = 990
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