Advertisements
Advertisements
प्रश्न
A compound made up of two elements X and Y has an empirical formula X2Y. If the atomic weight of X is 10 and that of Y is 5 and the compound ha a vapor density 25, find its molecular formula.
उत्तर
Empirical formula = X2Y
Atomic Weight (X) = 10
Atomic Weight (Y) = 5
Empirical Formula Weght = 2 × 10 + 5 = 25
So, n = `"Molecular weight"/"Empirical formula weight" = (2xx"V.D")/"Empirical formula weight"`
`n = (2 xx 25)/25 = 2`
So Molecular Formula = (X2Y) × 2 = X4Y2
APPEARS IN
संबंधित प्रश्न
Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]
Explain the terms empirical formula and molecular formula.
Give the empirical formula of CH3COOH
Give example of compound whose:
Empirical formula is the same as the molecular formula.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
The percentage composition of sodium phosphate, as determined by analysis is : 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound.
[H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]
Calculate the percentage of water of crystallization in CuSO4. 5H2O
(H = 1, O = 16, S = 32, Cu = 64)
Give the empirical formula of C6H18O3
A compound is formed by 24 g of X and 64 g of oxygen. If the atomic mass of X = 12 and O = 16, calculate the simplest formula of the compound.
Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.
