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प्रश्न
A compound X is formed by the reaction of a carboxylic acid C2H4O2 and an alcohol in presence of a few drops of H2SO4. The alcohol on oxidation with alkaline KMnO4 followed by acidification gives the same carboxylic acid as used in this reaction. Give the names and structures of
- carboxylic acid
- alcohol and
- the compound X.
Also write the reaction.
उत्तर
When ethanoic acid (C2H4O2) reacts with absolute ethanol (C2H6O) in the presence of an acid catalyst, the ester is formed. So, compound X is ethyl ethanoate.
\[\ce{CH3COOH + CH3CH2OH -> \underset{Ester}{CH3COOC2H5} + H2O}\]
Ethanol on oxidation with alkaline KMnO4 gives ethanoic acid.
\[\ce{C2H5OH\overset{Alkaline KmnO4}{ ->}CH3COOH}\]
- Ethanol on oxidation with alkaline KMnO4 gives ethanoic acid.
\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{O}\phantom{....}\\
|\phantom{....}||\phantom{....}\\
\ce{H - C - C - O - H}\\
|\phantom{.........}\\
\ce{H}\phantom{.........}\\
\end{array}\] - Ethanol
\[\begin{array}{cc}
\ce{H}\phantom{....}\ce{H}\phantom{....}\\
|\phantom{....}|\phantom{....}\\
\ce{H - C - C - O - H}\\
|\phantom{....}|\phantom{.....}\\
\ce{H}\phantom{...}\ce{H}\phantom{.....}\\
\end{array}\] - Compound x is ethyl ethanoate (ester).
\[\begin{array}{cc}
\phantom{.........}\ce{H}\phantom{...}\ce{O}\phantom{.......}\ce{H}\phantom{...}\ce{H}\phantom{.........}\\
|\phantom{....}||\phantom{........}|\phantom{....}|\\
\ce{H - C - C - O - C - C - H}\\
\phantom{.}|\phantom{.............}|\phantom{....}|\phantom{.}\\
\phantom{.}\ce{H}\phantom{............}\ce{H}\phantom{...}\ce{H}\phantom{.}
\end{array}\]
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|\phantom{..}\\
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|\\
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\end{array}\]