Question

A conductivity cell having cell constant 8.76 cm⁻¹, placed in 0.01 M solution of an electrolyte offered a resistance of 1000 ohms. What is the specific conductance of electrolytes?

पर्याय

• 8.76 × 10⁴ ohm⁻¹ cm⁻¹

• 8.76 × 10⁻⁴ ohm⁻¹ cm⁻¹

• 8.76 × 10⁻³ ohm⁻¹ cm⁻¹

• 8.76 × 10⁻² ohm⁻¹ cm⁻¹

Answer 1

8.76 × 10⁻³ ohm⁻¹ cm⁻¹

Explanation:

Specific conductance (κ) = `"G"."l"/"a" = 1/"R"."l"/"a"`

= `1/1000 xx 8.76`

= 8.76 × 10⁻³ ohm⁻¹ cm⁻¹